each side of a rectangle is doubled find the ratio between the perimeters of the original rectangle and the resulting rectangle and find areas of the original rectangle and the resulting rectangle
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Let perimeter of original rectangle be P1
Perimeter of resulting rectangle be P2
P1=2(l+b)
P2=2(2l+2b)
So,
P1/P2=2(l+b)/4(l+b)=2/4=1/2
P1:P2=1:2
Area A1=lb
Area A2=4lb
A2=4A1
Perimeter of resulting rectangle be P2
P1=2(l+b)
P2=2(2l+2b)
So,
P1/P2=2(l+b)/4(l+b)=2/4=1/2
P1:P2=1:2
Area A1=lb
Area A2=4lb
A2=4A1
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