each side of a rhombus is 13 centimetre and one diagonal is 10 centimetre find 1)the length of its other diagonal 2) to the area of the Rhombus
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The diagonals of rhombus bisect each other at right angle. Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O. AC = 10 cm , OA =1/2×AC= OA= (½) × 10= 5 cm OA= 5 cm AB = 13 cm (given) In ∆ AOB By Pythagorean theorem AB²= 0B²+ OA² 13² = OB² + 5² 169 = OB² + 25 OB²= 169 – 25 OB² =144 OB= √144 OB= 12 cm Diagonal BD = 2 x 12= 24 cm Hence, the length of other Diagonal = 24 cm HOPE THIS WILL HELP YOU....
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saksham7183:
thanks a lot
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