Each side of a rhombus is 13 cm and one diagonal is 10 cm.Find : the length of its other diagonal
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5 square+ob square=13 square
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the rhombus ABCD ( let be the name )
GIVEN-
each sides of rhombus = 13 cm
one diagonal AC = 10 cm
draw another diagonal BD
as we know that the diagonals of rhombus bisect each other at 90 degree.
so O is the point in which the diagonals bisect.
So AO = OC = 5cm
and BO = OD
now,
triangle AOD is right angle triangle
triangle DOC is right angle triangle
triangle COB is right angle triangle
triangle BOA is right angle triangle
(we can take any one )
AOD
= (AO)^2 + (OD)^2 = AD^2
= (5)^2 + (OD)^2 = 13^2
= 25 + (OD) ^2 = 169
= (OD)^2 = 169-25
= (OD)^2 = 144
= OD =√144
= OD = 12
as BO = OD,
and BO = 12cm than OD also = 12cm
now diagonal AC = BO +OD
AC = 12 + 12
AC = 24 cm.
GIVEN-
each sides of rhombus = 13 cm
one diagonal AC = 10 cm
draw another diagonal BD
as we know that the diagonals of rhombus bisect each other at 90 degree.
so O is the point in which the diagonals bisect.
So AO = OC = 5cm
and BO = OD
now,
triangle AOD is right angle triangle
triangle DOC is right angle triangle
triangle COB is right angle triangle
triangle BOA is right angle triangle
(we can take any one )
AOD
= (AO)^2 + (OD)^2 = AD^2
= (5)^2 + (OD)^2 = 13^2
= 25 + (OD) ^2 = 169
= (OD)^2 = 169-25
= (OD)^2 = 144
= OD =√144
= OD = 12
as BO = OD,
and BO = 12cm than OD also = 12cm
now diagonal AC = BO +OD
AC = 12 + 12
AC = 24 cm.
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