each side of a rhombus is 13 cm and one of its diagonal is 10 cm.Find the length of its other diagonal and the area of the rhombus
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HEYA!!
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⭐Let ABCD be a Rhombus with AB=BC=CD=AD=13 cm.
Now given that Diagonal AC =10 cm
Then OC = OA = 5 cm .
Now Apply Pythagoras theorem in ∆ AOD ,
We have ,
13^2 = 5^2 + OD^2
169 - 25 = OD^2
OD^2 = 144
OD = 12 cm
Diagonal = 24 cm
⭐Area of Rhombus = 1/2 × 24 × 10
= 120 cm^2 .
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---------
⭐Let ABCD be a Rhombus with AB=BC=CD=AD=13 cm.
Now given that Diagonal AC =10 cm
Then OC = OA = 5 cm .
Now Apply Pythagoras theorem in ∆ AOD ,
We have ,
13^2 = 5^2 + OD^2
169 - 25 = OD^2
OD^2 = 144
OD = 12 cm
Diagonal = 24 cm
⭐Area of Rhombus = 1/2 × 24 × 10
= 120 cm^2 .
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