Question

Each side of a square field is 50 m long. A barricade is to be placed along the diagonal of the field. Find the length of the barricade​.

No Spam Plz !
Challenge to Stars and Mods

Answer 1

$\underline{\underline{\sf{\maltese\:\:Question}}}$

• Each side of a square field is 50 m long. A barricade is to be placed along the Diagonal of the field. Find the Length of the Barricade​.

$\underline{\underline{\sf{\maltese\:\:Given}}}$

• Field is in Square Shape

• Side of a square field = 50 m long

$\underline{\underline{\sf{\maltese\:\:To\:Find}}}$

• Length of the Barricade​

$\underline{\underline{\sf{\maltese\:\:Answer}}}$

• Length of the Barricade​ = 70.71 m

$\setlength{\unitlength}{2cm}\begin{picture}{\sf }\put(3.17,0.9){\sf }\put(3.17,3){\sf }\put(0.7,3){\sf }\qbezier(1,1)(1,1)(3,1)\qbezier(3,1)(3,1)(3,3)\qbezier(3,3)(3,3)(1,3)\qbezier(1,3)(1,3)(1,1)\qbezier(1,3)(1,3)(3,1)\put(4,2){\sf }\end{picture}\bigstar\:\:\:\large\textbf{Length of Baricade = 70.71 m}\:\:\:\bigstar$

 

$\underline{\underline{\sf{\maltese\:\:Calculation}}}$

We need to know about some basic terms before going to Calculations

• Square : Square is a simple closed figure with having 4 sides equal each angle measuring 90°. Square is also a Quadrilateral
• Diagonal : A line segment that goes from one corner to another

Properties of Square :

• Square Has All Sides Equal

• Each Angle will be 90°

• Number of sides = 4

• Number of vertices = 4

• Length of diagonals is greater than the sides of the square

• Two diagonals of the square are equal to each other

• Diagonals of the square bisect each other at 90°

• Al four sides of the square are congruent

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf }\put(-0.5,4.2){\bf }\put(4.2,-0.5){\bf }\put(4.2,4.2){\bf }\put(0.3,-0.8){\bf\large @RockingStarPratheek}\put(4.4,2){\bf\large }\end{picture}$

A diagonal divides a square into two Right-angled triangles

$\setlength{\unitlength}{1cm}\begin{picture}\put{\sf }\put(3.17,0.9){\sf }\put(3.17,3){\sf }\put(0.7,3){\sf }\qbezier(1,1)(1,1)(3,1)\qbezier(3,1)(3,1)(3,3)\qbezier(3,3)(3,3)(1,3)\qbezier(1,3)(1,3)(1,1)\qbezier(1,3)(1,3)(3,1)\put(4,2){\sf =}\qbezier(6,1)(6,1)(6,3)\qbezier(6,3)(6,3)(8,1)\qbezier(8,1)(8,1)(6,1)\put(6,3.1){\sf }\put(5.6,1){\sf }\put(8.2,1){\sf }\put(9,2){\sf+}\qbezier(11,3)(11,3)(13,3)\qbezier(13,3)(13,3)(13,1)\qbezier(13,1)(13,1)(11,3)\put(12.8,0.5){\sf }\end{picture}$

To Solve This Problem Further

• We need to Know About Pythagoras Theorem !!

Pythagoras Theorem : In a Right-angled triangle, the square of  Hypotenuse is equal to the sum of squares of the other two Sides

$\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(-1.1,2.5){\large\bf Side}\put(2.8,.3){\large\bf Side}\put(4.,2.5){\large\bf Hypotenuse}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf B}\put(5.8,.3){\large\bf C}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(4.9,3.4){\large\boxed{\sf @RockingStarPratheek}}\end{picture}$

(Hypotenuse)² = (Side)² + (Side)²

• From Our Square Diagonal is the Hypotenuse

⇒ (Hypotenuse)² = (50 m)² + (50 m)²

⇒ (Hypotenuse)² = 2500 m² + 2500 m²

⇒ (Hypotenuse)² = 5000 m²

⇒ √(Hypotenuse)² = √(5000 m²)

⇒ Hypotenuse = √5000 m

⇒ Hypotenuse = 70.71 m  

$\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(-1.1,2.5){\large\bf 50 m}\put(2.8,.3){\large\bf 50 m}\put(4.,2.5){\large\bf 70.71 m}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf B}\put(5.8,.3){\large\bf C}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(4.9,3.4){\large\sf @RockingStarPratheek}\end{picture}$

_______________________________

Request :

If there is any difficulty viewing this answer in app, Kindly see this answer at Web (https://brainly.in/) for clear steps and understanding.

See the answer at :

https://brainly.in/question/31590245

Answer 2

Answer:

given:- the length of the sides of the square field is 50m.

according to the question, a barricade is to be place along tge diagonal of tge field.

now, if we divide the square in two triangles by the diagonal. we get two right angle triangle where sides are the base and perpendicular and diagonal is the hypotenuse.

-> d²= s² + s²

-> d²= 50² + 50²

-> d²= 2500 + 2500

-> d = root 5000

-> d = 70.71m (approximately)

hence, the length of the barricade is 70.71m.

I HOPE ITS HELP YOU,.........