Each side of a square field measures 21 m. Adjacent to this field, there is a rectangular field having its sides in the ratio 4 : 3.If the perimeters of both the fields are equal, find the dimensions of the rectangular field.
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Answer:
length-24 m width-18 m
Step-by-step explanation:
Perimeter of the square=21+21+21+21
=84 m
Therefore the perimeter of the rectangle is 48 m
The ratio of the sides of the rectangle is 4:3
hence 84*4/7 will give the total length-48 divide by 2 since it is of the two lengths to give 24 m
84*3/7 for the width which is 36 divide by two to give 18 m
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