each side of a square subtends an angle of 60°at the top of a tower of heiggt h metres standing at the square.if l is the length of each side of the square,then what is h² equal to?
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i know but i didnt explain now
Step-by-step explanation:
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Question:- Each side of a square subtends an angle of 60 degree at the top of a tower h meters high standing in the centre of the square.If 'a' nis the length of each side of square, then prove that 3a2 = 2h2.
Answer:
Step-by-step explanation:
Keeping in view the attached image;
Since the sides of the square is a, the length of the diagonal is;
AC= √2a
So,
OA=AC/2
As, OB=h
In the triangle AOB,
tan60°=OB/OA
√3=h÷a/√2
√3a=√2h
When we square on both sides;
3²=2h²
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