each side of a triangle ABC is 12 units .D is the foot of the perpendicular dropped from A on BC,and E is the midpoint of AD.the length of BE in the same unit is
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According to question
In triangle ABC
AB = BC = AC = 12 units
When perpendicular is drawn from A to D at BC
Then
BD = DC = 12/2 = 6 units
Now in triangle ADB
AB^2 = BD^2 + AD^2
Thus
AD^2 = 12^2 - 6^2
AD^2 = 144 - 36
AD^2 = 108
So AD = 10.39
Thus ED = 5.19
Now in triangle EDB
BE^2 = ED^2 + BD^2
So
BE^2 = 26.93 + 36
BE = 7.93
In triangle ABC
AB = BC = AC = 12 units
When perpendicular is drawn from A to D at BC
Then
BD = DC = 12/2 = 6 units
Now in triangle ADB
AB^2 = BD^2 + AD^2
Thus
AD^2 = 12^2 - 6^2
AD^2 = 144 - 36
AD^2 = 108
So AD = 10.39
Thus ED = 5.19
Now in triangle EDB
BE^2 = ED^2 + BD^2
So
BE^2 = 26.93 + 36
BE = 7.93
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