Eample 8.8 A 400 kg satellite is in a
circular orbit of radius 2R, about the
Earth. How much energy is required to
transfer it to a circular orbit of radius 4R?
What are the changes in the kinetic and
potential energies ?
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Solution :
Here, m=400,
RE=6.37×106m
Initial total energy, Ei=PE+KE
=−GMmr+12mυ20=−GMmr+12m(GMr)
=−GMm2r=−GMm2×(2RE)=−GMm4RE
Final total energy, Ef=−GMm2×(4RE)=−GMm8RE
The change in total energy is, ΔE=Ef−Ei
−GMm8RE−(−GMm4RE)=GMm8RE
=(GMR2E)×mRE8=gmRE8
=(9.81)×(400)×(6.37×106)8
=3.13×109J Thus, teh energy required to transfer the satllite to the desired orbit =3.13×109J
the decrease in K.E.=Ki−Kf
=12m(GM2RE)−12m(GM4RE)
=18GMmRE=gmRE8=3.13×109J
Gain in P.E.=Uf−Ui
=−GMm4R−(−GMm2R)=GMm4R
=gmRE4=2×3.13×109J=6.26×109J
Thus, the again in P.E. is twice the loss in
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