let ABCD be a parallelogram of area 124 cm.it E and F are the midpoint of side AB and CD respectively ,then find area of parallelogram AEFD
aaliya57:
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Answered by
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area of parallelogram= bh
As base in AEFD is b/2 whereas h remain same so it area is bh/2 that is
124/2=62
As base in AEFD is b/2 whereas h remain same so it area is bh/2 that is
124/2=62
Answered by
488
ABCD be a parallelogram.
Area of parallelogram = 124 cm² (Given)
Consider a point P and join AP which is perpendicular to DC.
Now, Area of parallelogram EBCF = FC x AP and
Area of parallelogram AFED = DF x AP
Since F is the mid-point of DC, so DF = FC
From above results, we have
Area of parallelogram AEFD = Area of parallelogram EBCF = 1/2 (Area of parallelogram ABCD)
= 124/2
= 62
Area of parallelogram AEFD is 62 cm².
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