Easy Question..!
✠ The potential energy of a body of mass 0.5 kg increases by 100 J when it is taken to the top of a tower from the ground. If force of gravity on 1 kg is 10 N, what is the height of the tower ?
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Answers
Answer
Given that,
Mass of body M=0.5kg
Potential energy P.E=100J
Force of gravity on 1 kg is 10 N
Now,
F=mg
10=1×g
g=10m/s 2
Now, change in Potential energy
=mg(h 2−h1 )
=mg(h−0)
=mgh
Now, the height is
100=mgh
h= 0.5×10
100
Given:
✰ Mass of body ( M ) = 0.5 kg
✰ Potential energy ( PE ) = 100 J
✰ Force of gravity on 1 kg is 10 N
To find:
✠ The height of the tower.
Solution:
As the value of force and mass is already given i.e., mass is 1 kg and force on 1 kg mass is 10 N,So we will find gravity by using formula ( F = mg ). Putting the values in the formula we can easily calculate gravity. Now, we know that change in potential energy is given by mgh then putting the values in the formula we can easily calculate the height of the tower.
☣ F = mg
Put the values in,
➺ 10 = 1 × g
➺ g = 10/1
➺ g = 10 m/s²
➺ Change in potential energy = mg ( h₂ - h₁ )
➺ Change in potential energy = mg ( h - 0 )
☣ Change in potential energy = mgh
Put the values in the formula to calculate the height of the tower.
➺ 100 = 0.5 × 10 × h
➺ 100 = 5 × h
➺ h = 100/5
➺ h = 20 m
∴ The height of the tower is 20 m
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