easy solution to solve the question: the question is: prakash got 30%marks in an exm and failed by 6 marks, sudhir got 40% marks which are 6 more than the minimum marks ,required to pass. find the max. marks and min% of marks required to pass
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Let the total marks be x
prakash case
To pass, he should get,
(30%of x) +6
Sudhir case,
To pass, he should get,
(40% of x) -6
∴(30%of x) +6=(40% of x) -6
⇒0.3x +6 = 0.4x -6
⇒0.1x = 12
⇒x = 120 marks
Full marks = 120 marks
Pass marks will be (30%of x) +6
=(30%of 120) +6
=36+6
=42 marks
prakash case
To pass, he should get,
(30%of x) +6
Sudhir case,
To pass, he should get,
(40% of x) -6
∴(30%of x) +6=(40% of x) -6
⇒0.3x +6 = 0.4x -6
⇒0.1x = 12
⇒x = 120 marks
Full marks = 120 marks
Pass marks will be (30%of x) +6
=(30%of 120) +6
=36+6
=42 marks
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