Question

Ecaluate:
Cot12°:Cot38°:Cot52°:Cot60°:Cot78°.

Answer 1

Solution :

Correction

Evaluate:

Cot12°:Cot38°:Cot52°:Cot60°:Cot78°.

Convert them by using (90 - theta ) Concept

⇒ cot 12° × cot 38° × cot 52° × cot 60° × cot 78°

⇒ Cot 12° × Cot 38° × Cot ( 90 - 52 ) × 1/√3 × Cot ( 90 - 78 )

⇒ Cot 12° × Cot 38° × tan 78° × 1/√3 × tan 52°

Rearrange them

cot 78° × cot 12° ) × ( cot 52° × cot 38° ) × cot 60°

⇒ 1 * 1 * 1/√3

⇒ 1/√3

Answer 2

bonjour happy makhar shankranti



here is some misunderstanding in your question

so the correct question is there

⬆️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️⬇️

tan12^ cot38^cot52^ cot60^tan78^


so the answer is
tan12^ cot38 cot(90-38) cot60 tan(90-12)

tan12 cot38 tan38 cot60 cot12

tan12 ×1/tan12 ×cot38×1/cot38 ×cot60


so cancel the value and left value is cot60


then cot60 =1//3

1by root3

hey sorry I don't know the symbol of degree ⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️⬆️





again happy makar shankranti
be brainly✒✒✒