effect on pressure if the area is doubled keeping force constant
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Answered by
0
Hello Dear !
_________________________________________________________
As you know ,
P = F/A
where P = pressure
F = Force
A = Area
__________________________________________________________
if the area is doubled Then the pressure applied is halved
see...
let P1 = F/A
then P2 = F/2A
P1/P2 = A/2A
P1/P2 = 1/2
__________________________________________________________
_________________________________________________________
As you know ,
P = F/A
where P = pressure
F = Force
A = Area
__________________________________________________________
if the area is doubled Then the pressure applied is halved
see...
let P1 = F/A
then P2 = F/2A
P1/P2 = A/2A
P1/P2 = 1/2
__________________________________________________________
Answered by
0
Pas. = N/m²
Let us assume N = 1 and m = 1
Pas. = 1/(1)²
Pas. = 1
Now,
Let the area, m= 2
Pas. = 1/(2)²
Pas. = 1/4
Pas. = 0.25
Here the pressure becomes ¼. That is pressure decreases.
I hope this will help you.
Let us assume N = 1 and m = 1
Pas. = 1/(1)²
Pas. = 1
Now,
Let the area, m= 2
Pas. = 1/(2)²
Pas. = 1/4
Pas. = 0.25
Here the pressure becomes ¼. That is pressure decreases.
I hope this will help you.
sakshamgupta:
thanks
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