Question

pls answer this question

Answer 1

Hello dear !
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Given      : BA║ED, BC║EF
To prove : ∠ABC = ∠DEF
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Proof :
Extend DE that meet BC on P 
Extend EF that meet AB on Q
So, BPEQ is formed a ║gm ∵ BP║EQ,EP║BQ
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In ║gm BPEQ
       ∠ABC  = ∠ PEQ _________(1)
also ∠PEQ = ∠DEF [VOA's]____(2)
By (1) And (2) we get 
∠ABC = ∠DEF 
hence proved :)
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