Question

Effective atomic number of central metal ion of K3FE(CN)6

Answer 1

Explanation:

effective atomic number =atomic number of Fe-charge on Fe+6multipled by 2

Answer 2

Answer:

$36$

Explanation:

• We know that the atomic number of $Fe$ is $26$.

• The formula for effective atomic number is: $Atomic \ number - (Oxidation \ number \times Coordination \ number)$

The oxidation number will be=

$4 + x - 6 = 0\\x-2 = 0 \\x=+2$

The co-ordination number will be=

$2 \times 6 = 12$

Therefore, effective atomic number=

$Atomic \ number - (Oxidation \ number \times Coordination \ number)$

Substituting the values in the above equation we get,

Effective Atomic Number = $26-(2 \times 12)$ = $36$

Hence, the Effective Atomic Number of central metal ion of $K_{3} Fe(CN)_{6}$ is $36$.