∠EFG and ∠GFH are a linear pair, m∠EFG=3n+22, and m∠GFH=2n+23. What are m∠EFG and m∠GFH?
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APQ
3n+22+2n+23=180
5n+45=180
5n=180-45=135
n=135/5=27
Now,
angle EFG=3x27+22=103°
angle GFH=2x27+23=77°
Now,you can find the other angles by your own....
Hope you will understand... Thank You....
How did you gave the symbol of angle...??
Do you use any different keyboard...?
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