EFGH is a rectangle and L, M, N and O are mid-points of the sides EF, FG, GH and HE respectively. Show that the quadrilateral LMNO is a rhombus.
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Answers
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Step-by-step explanation:
Area of HFG=
2
1
× Area of HDCF (Parallelogram and triangle on same base)
Multiplying by 2
2× Area of HGF=2×[
2
1
×AreaHDCF]
Area of HGFE =
2
1
×ABCD
Hence proved.
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