Question

Ehen an ideal gas (gama=5/3) is heated under constant pressure then what percentage of given heat energy will be utilised in doing external work

Answer 1

we are given heated in constant pressure so

Q= mCp ΔT

ΔU= m Cv ΔT

W= Q- ΔU

We need to find W/Q

= (Q- ΔU)/ Q = 1 - mCvΔT/mCpΔT= 1 - Cv/Cp

Cp/Cv= Υ = 5/3 so Cv/Cp= 3/5

⇒ W/Q = 1 - 3/5 = 2/5

now percentage 2/5 × 100 = 40%

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Answer 2

Answer:

40%

Explanation:

Q= mCp ΔT

ΔU= m Cv ΔT

W= Q- ΔU

We need to find W/Q

= (Q- ΔU)/ Q = 1 - mCvΔT/mCpΔT= 1 - Cv/Cp

Cp/Cv= Υ = 5/3 so Cv/Cp= 3/5

⇒ W/Q = 1 - 3/5 = 2/5

now percentage 2/5 × 100 = 40%

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REGARDS