Question

Eight mercury droplets having a radius of 1 mm and charge of 0.066pc each merge to form one droplets it's potential is

Answer 1

Answer:

Explanation:

◆ Answer -

V = 2.376 V

● Explanation -

When 8 drops are merged to form one big drop, radius of bigger drop is calculated as -

R = ∛n × r

R = ∛8 × 1

R = 2 mm

R = 2×10^-3 m

Total charge on 8 drops is -

Q = n × q

Q = 8 × 0.066

Q = 0.528 pC

Q = 5.28×10^-13 C

Potential of the bigger drop is -

V = 1/4πε × Q / r

V = 9×10^9 × 5.28×10^-13 / 2×10^-3

V = 2.376 V

Therefore, potential of the bigger mercury drop is 2.376 V.