Eight STD find the length of the diagonal of a rectangle whose length is eight CM and width is sixc
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let's divide the rectangle into 2 triangles
By Pythagoras theorem,
a^2=b^2+c^2
a^2=8^2+6^2
a^2=64+36
a^2=100
a=√100
a=10
Hence the length of the diagonal is 10 cm
By Pythagoras theorem,
a^2=b^2+c^2
a^2=8^2+6^2
a^2=64+36
a^2=100
a=√100
a=10
Hence the length of the diagonal is 10 cm
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