Math, asked by aqibshaikh112, 1 year ago

Eight times a two digit number is equal to three times the number reversing

Answers

Answered by nudhirsaini88
0

Let the digit in the ones place be y and tens place be x Therefore the number = 10x + y Number formed by reversing the digits = 10y + x Given 8(10x + y) = 3(10y + x) ⇒ 80x + 8y = 30y + 3x ⇒ 77x – 22y = 0 ∴ 7x – 2y = 0 → (1) It is also given that the difference between the digits is 5. Hence (y – x) = 5 – x + y = 5 → (2) Multiply equation(2) with 2 and add to equation (1), we get 7x – 2y = 0 –2x + 2y = 10 ---------------- 5x = 10 ∴ x = 2 Put x = 2 in – x + y = 5, we get – 2 + y = 5 ⇒ y = 7 Hence the number = (10x + y) = (10×2 + 7) = 27

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Answered by arnab2261
0
 {\huge {\mathfrak {Answer :-}}}

➡️ 10x + y.

➡️ Reversed = 10y + x.

▪️By condition,

8(10x + y) = 3(10y + x)

Or, 80x + 8y = 30y + 3x.

Or, 77x = 22y.

Or, 7x = 2y.

Or, x = 2y/7.

▪️Again, it is given that the difference between them is 5.

So,

y - x = 5.

Or, y - 2y/7 = 5.

Or, 5y/7 = 5.

Or, y = 7.

▪️And,

x = 7 - 5 = 2.

✨ Hence, the number is

= 2 * 10 + 7.

= 27.

That's it..
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