Question

eight years hence a mans age will be double the age of his son and eight years ago he was six times as old as his son. find their present ages. using linear equation​

Answer 1

Answer:

32 and 12

Step-by-step explanation:

let x and y be ages of man and his son respectively

After 8 yrs,

x+8=2(y+8)

x+8=2y+16

x=2y+8

Before 8 yrs,

(x-8)=6(y-8)

x-8=6y-48

x=6y-40

Using the 2 eqns,

2y+8=6y-40

4y=48

y=12, x= 32