Eighteen balls are kept in a box some balls are red and remaining balls are blue. twice the number of red balls exceeds thrice the number of blue balls by 1 .the number of red balls in the box is
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let number of blue balls = n
∴ total balls = (n+5)
P(blue ball) = n+5n
P(red ball) = n+55
as per question,
P(blue ball) = 3 × P(red ball)
n+5n = 3×n+55
∴n=15
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