Question

Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of the present ages of the son and the father is

Answer 1

Consider today's father age f

and son age s

first condition:

3(s-18)=f-18

3s-54=f-18           ..........(1)

Condition second:

2s=f                      ...........(2)

put this value in equation 1.

3s-54=2s-18

3s-2s=54-18

s=36

then,

2s=f

2*36=f

f=72

Addition of father and son age:s+f

                                                  =72+36

                                                   =108