Question

Divide 56 into three parts such that 3times the 1st part exceeds one third of the second by 48.The part is

Answer 1

Let the 1st part be x.

Therefore, 2nd part=56-x

3 times first part=3*x=3x

1/3rd of 2nd part=(56-x)/3

According to the question,

3x-(56-x)/3=48

or, 9x-56+x=144

or,10x=144+56

or 10x=200 or, x=20

Therefore, 1st part=20 and

2nd part=(56-20)=36.

Ans:The parts are 20 and 36.