Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ?
A) 84 yrs
B) 96 yrs
C) 116 yrs
D) 108 yrs
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let D=daughter’s age
3D= Mother’s age (because the word “of” means to multiply and Mother is 3 times the age of the Daughter)
and in 4 years after they BOTH increase in age by 4 years, their ages will add up to 60:
(D+4)+(3D+4)=60
3D= Mother’s age (because the word “of” means to multiply and Mother is 3 times the age of the Daughter)
and in 4 years after they BOTH increase in age by 4 years, their ages will add up to 60:
(D+4)+(3D+4)=60
Answered by
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Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ?
A) 84 yrs
B) 96 yrs
C) 116 yrs
D) 108 yrs
Answer: D)108 yrs
A) 84 yrs
B) 96 yrs
C) 116 yrs
D) 108 yrs
Answer: D)108 yrs
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