Eind the area
of shaded
portion ?
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Answer:
In right triangle ABC, we have
AC²=AB²+BC²
AC²=(8)² + (6)²
AC²=64+36
AC²=100
AC=√100
AC=10cm
R= 10/2cm
R=5cm
Area of shaded region = ar(traingleABC) + (area of semicircle AC) - ar(quadrantBCP)
=(1/2×6×8) + 1/2×22/7×5×5 - (22/7 ×5×5×90°)/360°
=24 + 550/14 - 275/14
= (336+550-550)/14
=336/14
=24cm²
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