Question

Eind the sum of first 100 terms of A.P. 14, 16, 18,
Here a= 14, d = 2, n = 100
Sn = [+ (n-1)d]
100
S100
[ +(100-1)x 2]
2
= 50 [[ + ]
= 50 x 6
Sum of first 100 terms of given A.P. is​

Answer 1

Answer:

AP = 14, 16, 18.......

Here, a= 14

d= 2

n= 100

Sn = n/2 [2a + (n-1)d]

= 100 /2 [ 2 (14) + (100-1) (2) ]

= 50 [ 28 + (99)(2)]

= 50 [ 28 + 198]

= 50 [ 226]

= 11300