एक चिटीं 12cm ऊचे खम्भे पर एक मीनट में 3cm ऊपर चढता और दुसरे मीनट में 2cm निचे फिसल जाता है तो कितने समय में चिटीं (a)खम्भे की चोटी पर पहुंच जाऐगी? (b) खम्भे को पार कर जाएगी?
एक चिटीं 12cm ऊचे खम्भे पर एक मीनट में 3cm ऊपर चढता और दुसरे मीनट में 2cm निचे फिसल जाता है तो कितने समय में चिटीं (a)खम्भे की चोटी पर पहुंच जाऐगी? (b) खम्भे को पार कर जाएगी?
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8minutes and cross in 9minute
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Answer:
a). The ant will reach the top of the tower in 19 minutes
b). Time taken by the ant to cross the tower = 19 + 2 = 21 minutes
Step-by-step explanation:
The total height of the tower = 12 cm
In first minute, distance traveled = 3 cm,
But the next minute, the ant falls 2 cm down
So, Distance traveled in 2 minutes = 1 cm
So, in 1 minute distance climbed = 0.5 cm
⇒ In 18 minutes, Distance climbed = 18 × 0.5 = 9 cm
The next minute it travels 3 cm so the distance traveled = 9 + 3 = 12 cm
Hence, the ant will reach the top of the tower in 19 minutes
Also, to cross the tower it needs 2 minutes more, So, Time taken by the ant to cross the tower = 19 + 2 = 21 minutes
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