Question

एक चिटीं 60cm ऊचे खम्भे पर एक second में 9cm ऊपर चढता और दुसरे second में 2cm निचे फिसल जाता है तो कितने समय में चिटीं खम्भे की चोटी पर पहुंच जाऐगी?

Answer 1

I am writing in english cause I am using a keyboard and don't know hindi typing.

We will calculate the net movement of ant in two seconds

1st second;9cm

2nd second;(-2cm)

so its net movement is 9-2=7 metre in 2 seconds.

NOW DIVIDE 60CM BY 7 .

WE WILL GET 60/7=8 (REMAINDER = 4)

SO NO. OF SECONDS ANT HAS TAKEN TO CLIMB 56 CM IS 8×2=16 SEC

SO ANT HAS COVERED 56 CM IN 16 SEC

NOW WHEN IT WILL CLIMB 9CM IN NEXT SECOND , IT WILL HAVE REACHED THE TOP. SO THE ANSWER IS 16+1 = 17 SEC

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