Question

एक्स एक्स स्क्वायर माइनस टू एक्स माइनस 8 एक्स स्क्वायर माइनस टू एक्स माइनस 8 ​

Answer 1

Given:

$\bold{x^2-2x-8=0}$

To find:

zeros=?

Solution:

In the given question, there is some mistyping error so the correct equation can be defined as follows:

$\bold{x^2-2x-8=0}$

compare the above value with:

$ax^2+bx+c=0\\\to a= 1\\\to b= -2\\\to c= -8$

formula:

$\bold{\frac{-b\pm\sqrt{b^2-4ac}}{2a}}$

put the a,b, and c value in the above formula:

$\to x= \frac{-(-2)\pm \sqrt{(-2)^2-4\times 1\times (-8)}}{2\times 1}\\\\\to x= \frac{2\pm \sqrt{4+32}}{2}\\\\\to x= \frac{2\pm \sqrt{36}}{2}\\\\\to x= \frac{2\pm6}{2}\\\\\to x= \frac{2(1\pm3)}{2}\\\\\to x= (1\pm3)\\\\\to x= (1+3) \ \ \ \ and \ \ \ \ x= (1-3)\\\\\to x= 4 \ \ \ \ and \ \ \ \ x= -2$