Question

एक संख्या तथा उसके योगफल का व्युत्क्रम 17/ 4 है तो एक संख्या ज्ञात करो?

Answer 1

HELLO DEAR,

LET THE NO BE X

$x + \frac{1}{x} = \frac{17}{4} \\ = > \frac{ {x}^{2} + 1}{x} = \frac{17}{4} \\ = > 4 {x}^{2} + 4 = 17x \\ = > 4 {x}^{2} - 17x + 4 = 0 \\ = > 4 {x}^{2} - 16x - x + 4 = 0 \\ = > 4x(x - 4) - 1(x - 4) \\ = > (4x - 1)(x - 4) \\ = > x = \frac{1}{4} and \\ = x = 4$
I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

x+x1​=417​=>xx2+1​=417​=>4x2+4=17x=>4x2−17x+4=0=>4x2−16x−x+4=0=>4x(x−4)−1(x−4)=>(4x−1)(x−4)=>x=41​and=x=4​
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