Physics, asked by choudharysandip482, 6 months ago

एक उत्तल लेंस की फोकस दूरी 40 से.मी. हैं। लेंस की क्षमता की गणना कीजिए।

Answers

Answered by gumalaru

1

Answer:

2.5D

Explanation:

फोकस दूरी=40cm or 0.4m

क्षमता=1/फोकस दूरी

=1/0.4

=2.5D

Answered by snehadittyam

0

Explanation:

mujhe Nahi pata dost msphi Kar do.

Previous Question

Next Question

Similar questions

Science, 3 months ago

different types of experudnes...

English, 3 months ago

short summary of the adventures of toto class 9th...

Math, 3 months ago

find the valeu of 'K' for which the points we cellines a(7,-2) b (5,1) c(3,K) find the answar...

Science, 6 months ago

1. What if, there is no periodic motion. Justify your answer with reasons. 2. Compare and contrast between uniform and non-non-uniform motion with an example. Do you Which SDG goal would you and why? 3. Explain the following concept in your own word with everyday example. Force, work, displacement, velocity, acceleration, distance. 4. If a car is moving with a speed of 5Km/h on highway then...

Biology, 6 months ago

एन्जाइम क्या होते हैं? कोई दो उदाहरण लिखिए। ...

Science, 11 months ago

जल का संगठन लिखिए तथा शरीर में जल की क्या उपयोगिता है?

English, 11 months ago

The difference between the village school and city school in term of quality of teaching and learning?oppose the motion schooling in the village is more advantageous than schooling in the city.

Math, 11 months ago

General solution for tan 3x = - 1...