एक वृत्त के परिगत एक चतुर्भुज ABCD खींचा गया है (देखिए आकृति) ।
सिद्ध कीजिए : AB + CD = AD + BC
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Answer:
_ _ _ _ _ _ _ _ _ _
to prove : AB+CD=AD+BC | Af+BF=AB I
given: | AE+DE=AD I
Af=AE | BG+CG=BC I
BF=BG | DH+CH=DC l
CH=CG | I
DH=DE |_ _ _ _ _ _ _ _ _ _ l
Add Right side and left side equally
Af+BF+CH+DH=AE+BG+CG+DE
Ab dekho AF+BF=AB,CH+DH=DC,AE+DE=AD,BG+CG=BC
SO,
AB+DC=AD+BC
HENCE PROVED
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