Question

If (a-b)=3, (b-c)=5, (c-a)=1, then the value of a^3+b^3+c^3-3abc/a+b+c=?

Answer 1

Answer:

data is wrong

Step-by-step explanation:

its given

a-b = 3

b-c = 5

c-a = 1

Adding all

a+b+c -(a+b+c) = 3 + 5 + 1

0 = 9

not possible

data is wrong