एक वर्ग के रूप में तार 144 cm- का क्षेत्रफल
घेरती है । यदि इसी तार को एक आयत के रूप में
मोड़ा जाए जिसकी लम्बाई 16 cm है, तो कितना
क्षेत्रफल घेरा जाएगा?
(1) 124 cm2
वर्ग
(2) 48.cm-
einmal
(3) 128 cm
ला
96 cm
36
Answers
Answer:
side = √144
= 12
p = 4 × 12
= 48
48 = 2 ( 16 + b )
24 = 16 + b
b = 24 - 16
= 8
A = 16×8 =128sq.cm
Given:
एक वर्ग के रूप में तार 144 cm- का क्षेत्रफल घेरती है । यदि इसी तार को एक आयत के रूप में मोड़ा जाए जिसकी लम्बाई 16 cm है, तो कितना क्षेत्रफल घेरा जाएगा?
A wire in the form of a square encloses an area of 144 cm². How much area is enclosed if the same wire is bent in the form of a rectangle of length 16cm?
To find:
कितना क्षेत्रफल घेरा जाएगा?
Solution:
The area of the square = 144 cm²
Let "a" be the side of the square.
We know,
∴
We know,
∴ The perimeter of the square = 4 × 12 = 48 cm
Since the same wire is bent to form a square and a rectangle, therefore Perimeter of the square = Perimeter of the rectangle
⇒ Perimeter of the rectangle = 48 cm
The length of the rectangle, l = 16 cm
We know,
∴
← breadth of the rectangle
We know,
Now,
The area of the rectangular wire is,
= 16 × 8
= 128 cm²
Thus, the enclosed area of the wire bent in the form of the rectangle is → 128 cm².
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