Math, asked by bishtanandsingh692, 4 months ago

एक वर्ग के रूप में तार 144 cm- का क्षेत्रफल
घेरती है । यदि इसी तार को एक आयत के रूप में
मोड़ा जाए जिसकी लम्बाई 16 cm है, तो कितना
क्षेत्रफल घेरा जाएगा?
(1) 124 cm2
वर्ग
(2) 48.cm-
einmal
(3) 128 cm
ला
96 cm
36​

Answers

Answered by prajapatsuresh951
10

Answer:

side = √144

= 12

p = 4 × 12

= 48

48 = 2 ( 16 + b )

24 = 16 + b

b = 24 - 16

= 8

A = 16×8 =128sq.cm

Answered by bhagyashreechowdhury
0

Given:

एक वर्ग के रूप में तार 144 cm- का क्षेत्रफल घेरती है । यदि इसी तार को एक आयत के रूप में मोड़ा जाए जिसकी लम्बाई 16 cm है, तो कितना क्षेत्रफल घेरा जाएगा?

A wire in the form of a square encloses an area of 144 cm². How much area is enclosed if the same wire is bent in the form of a rectangle of length 16cm?

To find:

कितना क्षेत्रफल घेरा जाएगा?

Solution:

The area of the square = 144 cm²

Let "a" be the side of the square.

We know,

\boxed{\bold{Area \:of\:a\:square = side^2 = a^2}}

a^2 = 144

\implies a = \sqrt{144}

\implies a =12 \:cm

We know,

\boxed{\bold{Perimeter \:of\:a\:square = 4 \times side = 4\times a}}

∴ The perimeter of the square = 4 × 12 = 48 cm

Since the same wire is bent to form a square and a rectangle, therefore Perimeter of the square = Perimeter of the rectangle  

Perimeter of the rectangle = 48 cm

The length of the rectangle, l = 16 cm

We know,

\boxed{\bold{Perimeter\:of\:a\:rectangle = 2 [l+b]}}

2 [l + b] = 48

\implies 2 [16 + b] = 48

\implies 16 + b= 24

\implies  \bold{b= 8\:cm} ← breadth of the rectangle

We know,

\boxed{\bold{Area \:of\:a\:rectangle = length \times breadth}}

Now,

The area of the rectangular wire is,

= 16 × 8

= 128 cm²

Thus, the enclosed area of the wire bent in the form of the rectangle is → 128 cm².

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Also View:

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