Question

Which of the following compounds does/do not contain any
atom with zero oxidation state?
C302
Br308
Na S406
Both (2) and (3)​

Answer 1

Answer:

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Answer 2

Answer:

Oxidation number of carbon in C

6

H

12

O

6

=

6

2×6−12

=0

Oxidation number of carbon in HCOOH=

1

2×2−2

=+2

Oxidation number of carbon in HCHO=

1

2×1−2

=0

Oxidation number of carbon in CH

4

=

1

2×0−4

=−4