Math, asked by raushankumar29319, 10 months ago

एकA.P के 3 पदों का योग 36 है तथा उनका गुणनफल 1620 है तो A.P ज्ञात करें​

Answers

Answered by Anurag739874
0

Answer

Step-by-step explanation:

Let the three term be (a-d),a,(a+d).

Then,we get

First step-

(a-d)+a+(a+d)=36.

a-d+a+a+d=36.

We know that Negative d and positive d is cancel out.

Then we get,

a+a=36.

2a=36.

a=36/2

a=18.

Then,

Equestion-2

(a-d)×a×(a+d)=1620.

Then, putting the value of"a"=18. In second equation (18-d)×18×(18+d)=1620.

(324-18d)×(18+d)=1620.

5832-324d+324d-18d^2=1620.

5832-1620=18d^2.

18d^2=4212

d^2=234.

d=√234.

d=15.29, something.

Then in supposing three putting the value of a and d in the equation then we get the three numbers.

Thank you

Ok

Is answer is fine.

Similar questions