एकA.P के 3 पदों का योग 36 है तथा उनका गुणनफल 1620 है तो A.P ज्ञात करें
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Step-by-step explanation:
Let the three term be (a-d),a,(a+d).
Then,we get
First step-
(a-d)+a+(a+d)=36.
a-d+a+a+d=36.
We know that Negative d and positive d is cancel out.
Then we get,
a+a=36.
2a=36.
a=36/2
a=18.
Then,
Equestion-2
(a-d)×a×(a+d)=1620.
Then, putting the value of"a"=18. In second equation (18-d)×18×(18+d)=1620.
(324-18d)×(18+d)=1620.
5832-324d+324d-18d^2=1620.
5832-1620=18d^2.
18d^2=4212
d^2=234.
d=√234.
d=15.29, something.
Then in supposing three putting the value of a and d in the equation then we get the three numbers.
Thank you
Ok
Is answer is fine.
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