Physics, asked by shrishmaharjan, 11 months ago

elastic limit of steel is 8×10^8 N/m^2 and young modulus 2×10^11 N/m^2 find the maximum elongation of half metre Steel wire that can be given without exceeding the elastic limit​

Answers

Answered by Anonymous
44

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ASSALAMUALAIKUM

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Given values:-

Elastic limit of steel i.e.

σ = 8 x10⁸ N/m²

Young modulus i.e.

Y =2.0 x10¹¹ N/m² 

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SOLUTION:-

maximum stress in the wire

σ= 8 x10⁸ N/m² 

Y =2.0 x10¹¹ N/m² 

Let the Length of the wire:-

L =0.50 m 

maximum elongation = l m 

Strain ε= l/L

=l/0.50

=2l 

Formulae :- σ/ε =Y 

▶ε =σ/Y 

▶2l = 8 x10⁸/2.0 x10¹¹ 

▶l =2/1000 m

= 2 mm

ANSWER:- 2 mm

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INSHAALLAH it will help you!

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Answered by suman682
22

maximum stress in the wire

σ= 8 x10⁸ N/m²

Y =2.0 x10¹¹ N/m²

Let the Length of the wire:-

L =0.50 m

maximum elongation = l m

Strain ε= l/L

=l/0.50

=2l

Formulae :- σ/ε =Y

▶ε =σ/Y

▶2l = 8 x10⁸/2.0 x10¹¹

▶l =2/1000 m

= 2 mm

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