Electric charges q q 2q are placed at the corners of an equilateral triangle
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Explanation:
i had given in the image
marks s brainlest
jay272
Correct question is :
Electric charges q q 2q are placed at the corners of an equilateral triangle then find force experienced by each charge.
Net force on 1 is √7(K.q.q)/a²
Net force on 2 is √7(K.q.q)/a²
Net force on 3 is √6(K.q.q)/a²
•let distance between each charge is a
•then ,
•On 1
F12 = (K.q.q)/a² = F (say)
F13 = (K.q.2q)/a² = 2kq²/a² = 2F
F²net = F² + 4F² + 2(F)(2F) cos60°
F²net = F² + 4 F² + 2F²
•F net = √7 F = √7(K.q.q)/a²
•On 2
F21 = (K.q.q)/a² = F (say)
F23 = (K.q.2q)/a² = 2kq²/a² = 2F
F²net = F² + 4F² + 2(F)(2F) cos60°
F²net = F² + 4 F² + 2F²
•F net = √7 F = √7(K.q.q)/a²
•On 3
F31 = (K.q.q)/a² = F (say)
F32 = (K.q.q)/a² = kq²/a² = F
F²net = F² + 4F² + 2(F)(F) cos60°
F²net = F² + 4 F² + F²
•F net = √6 F = √6(K.q.q)/a²
•Net force on 1 is √7(K.q.q)/a²
•Net force on 2 is √7(K.q.q)/a²
•Net force on 3 is √6(K.q.q)/a²