Physics, asked by tejarorasimran4919, 10 months ago

Electric charges q q 2q are placed at the corners of an equilateral triangle

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Answered by jay272
1

Explanation:

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Answered by AnkitaSahni
1

Correct question is :

Electric charges q q 2q are placed at the corners of an equilateral triangle then find force experienced by each charge.

Net force on 1 is √7(K.q.q)/a²

Net force on 2 is √7(K.q.q)/a²

Net force on 3 is √6(K.q.q)/a²

•let distance between each charge is a

•then ,

•On 1

F12 = (K.q.q)/a² = F (say)

F13 = (K.q.2q)/a² = 2kq²/a² = 2F

F²net = F² + 4F² + 2(F)(2F) cos60°

F²net = F² + 4 F² + 2F²

•F net = √7 F = √7(K.q.q)/a²

•On 2

F21 = (K.q.q)/a² = F (say)

F23 = (K.q.2q)/a² = 2kq²/a² = 2F

F²net = F² + 4F² + 2(F)(2F) cos60°

F²net = F² + 4 F² + 2F²

•F net = √7 F = √7(K.q.q)/a²

•On 3

F31 = (K.q.q)/a² = F (say)

F32 = (K.q.q)/a² = kq²/a² = F

F²net = F² + 4F² + 2(F)(F) cos60°

F²net = F² + 4 F² + F²

•F net = √6 F = √6(K.q.q)/a²

•Net force on 1 is √7(K.q.q)/a²

•Net force on 2 is √7(K.q.q)/a²

•Net force on 3 is √6(K.q.q)/a²

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