electric dipole is placed in uniform electric field at an angle of 60 degree with the uniform electric field of 6 N/C find (1) torque and (2) amount of work done required in displacing the angle from 30° to 90° if P is 12 microcoulomb meter.
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Answer:
TORQUE AND WORK DONE IS EQUAL TO √18
Explanation:
TORQUE
Tau=pE sin theta
WORK
W=pE(cos theta1 -cos theta2)
Just apply the formula u can get the answer
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