Question

electric dipole moment of cuso4 molecule is 3.2*10^-32cm. find the seperation between copper and sulphate ions

Answer 1

we know , dipole Moment = charge × distance between charges .
e.g P = Q × D
given , P = 3.2 × 10-³² Cm
and charge Cu+2 SO4-- Q = charge of 2 electrons

so,
3.2 × 10-³² = 2× 1.6 × 10^-19 × D

D = 10^-32+19 m = 10^-13 m

hence , distance between Cupper and sulphate ions = 10^-13m

Answer 2

Answer:

P = Q x D

3.2 x 10^-32 = 2 x 1.6 x 10^-19 x D

D = 3.2 x 10^-32 /2 x 1.6 x 10^-19

D = 10^-13

Explanation: Q= CU+2 SO4

2 electron = 2x 1.6x 10^-19