Physics, asked by tonysusanth2761, 1 year ago

Electric field at surfacedue to a solid sphere of uniform volume charge density

Answers

Answered by Ritammukherjee
0
Hi mate here is your answerr

The electric field of a sphere of uniform charge density and totalcharge charge Q can be obtained by applying Gauss' law. Considering a Gaussian surface in the form of asphere at radius r > R, the electric fieldhas the same magnitude at every point of the surface and is directed outward.

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Answered by Anonymous
0

Answer:

Explanation:Acceleration = (Final velocity - Initial velocity )/ Time

Acceleration = (0 - 50) /  5

Acceleration = -50 / 5

Acceleration = -10m/s^2

Hope this answer is correct..........

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