Electric field at surfacedue to a solid sphere of uniform volume charge density
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Hi mate here is your answerr
The electric field of a sphere of uniform charge density and totalcharge charge Q can be obtained by applying Gauss' law. Considering a Gaussian surface in the form of asphere at radius r > R, the electric fieldhas the same magnitude at every point of the surface and is directed outward.
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The electric field of a sphere of uniform charge density and totalcharge charge Q can be obtained by applying Gauss' law. Considering a Gaussian surface in the form of asphere at radius r > R, the electric fieldhas the same magnitude at every point of the surface and is directed outward.
Hope it helped you mate :-)
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Answer:
Explanation:Acceleration = (Final velocity - Initial velocity )/ Time
Acceleration = (0 - 50) / 5
Acceleration = -50 / 5
Acceleration = -10m/s^2
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