Question

. Electric field intensity between two infinite plane parallel sheets of charge of surface charge densities σ and -σ is *​

Answer 1

Explanation:

Electric field intensity due to one infinite plane sheet is σ /2€

Answer 2

Answer:

The electric field intensity between two infinite planes is $\frac{\sigma}{\epsilon}$ V/m.

Explanation:

Given:

$\sigma_{1}=\sigma c/m^{2}$

$\sigma_{2}=-\sigma c/m^{2}$

Here,

The surface charge density of infinite plane sheet 1 is denoted by $\sigma_{1}$.

The surface charge density of infinite plane sheet 2 is denoted by $\sigma_{2}$.

The electric field intensity due to infinite plane sheet 1 is denoted by $E_{1}$.

The electric field intensity due to infinite plane sheet 2 is denoted by $E_{2}$.

The resultant electric field intensity due to infinite plane sheets 1 and 2 is denoted by $E_{r}$.

Now,

By the equation,

$E_{r}=E_{1} -E_{2}$

$E_{r}=\frac{\sigma_{1}}{2\epsilon} -\frac{\sigma_{2}}{2\epsilon}$

$E_{r}= \frac{\sigma}{2\epsilon} -\frac{(-\sigma)}{2\epsilon}$

$E_{r}=$ $\frac{\sigma}{\epsilon}$ V/m

So, the electric field intensity between two infinite plane parallel sheets of charge of surface charge densities σ and -σ is equal to $\frac{\sigma}{\epsilon}$ V/m.