Question

Electric field intensity for electric dipole on y axis

Answer 1

Answer:

We can cancel this 2 with our 4 in the denominator and z times z squared will give us z cubed. Therefore, our electric field vector is going to be equal to q d divided by 2 Pi Epsilon zero z cubed. For the electric field of a dipole along its axis, z distance from its center such that z is much greater than d................................... ....

Answer 2

$\Huge\bf\purple{\mid{\overline{\underline{Answer}}}\mid}$

Electric Field Intensity :

The electric field intensity of any point is defined as the force experienced by unit positive charge placed at that point.

$\large\tt\red{E=\frac{F}{q_0}}$

The SI unit of electric field intensity

$\large \tt\orange{NC^{-1}}$

Electric field at any equatorial point of a dipole

$\large \tt{}is \: \: \: \green {\vec{E}=\frac{1}{4\pi\:\varepsilon_0}\frac{\vec{p}}{(r^2+a^2)^\frac{3}{2}}}$

At the mid-point of the dipole, r=0 so ,

$\large \tt \purple{\vec{E}=\frac{1}{4\pi\:\varepsilon_0}\frac{\vec{p}}{a^3}}$

$\huge{\mathfrak{\orange{hope\; it\; helps}}}$