Question

Electric intensity midway between the charge +1.67 x 10-C and -1.67 x 107C separated by
distance of 60 cm.
A. 3.33 x 104 Vm

B. 30.3 x 104 Vm

C. 1.67 x 108 Vm!

D. 30.3 x 104 Vm!​

Answer 1

Answer:

A. 3.33×10*4 V/m .. its per meter !

Explanation:

We have to calculate total of E by E1 + E2

E1 = Kq1/r*2

K=9×10*9

q=1.67×10*-7

r/d is taken as half i.e. 60/2=30cm=0.3m

E1=16700

E2 calculated same as above

E=E1 + E2 = 33400 = 3.33×10*4 V/m

Hope u understand nd got my point ..