electromagnetic radiations of wavelength 242nm is just sufficient to ionise sodium atom . then the ionisation energy of sodium in kj ÷mole is
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From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9m
C = 3 x 108 m/s
h = 6.62 x 10-34 Js
Now putting these values in the equation we get
E= (6.62 x 10-34 Js x 3 x 108 m/s) / (242 x 10-9m)
= 0.0821 x 10-17 J/atom
Or
E = (0.0821 x 10-17 ) / (1000 x 6.02 x 1023)
= 494 KJ/mol
C = 3 x 108 m/s
h = 6.62 x 10-34 Js
Now putting these values in the equation we get
E= (6.62 x 10-34 Js x 3 x 108 m/s) / (242 x 10-9m)
= 0.0821 x 10-17 J/atom
Or
E = (0.0821 x 10-17 ) / (1000 x 6.02 x 1023)
= 494 KJ/mol
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