Question

Electromagnetic wave is propagating in vacuum, at
a place magnitude of peak value of electric field is
V
24
The peak value of magnetic field at this
place is
(1) 8 x 104T
(2) 8 x 10-6T
(3) 8 x 10-8 T
(4) 8 x 10-10 T​

Answer 1

Answer:

As to the properties of electromagnetic radiation, I need first of all to come up with a little more than just words to the idea that a changing magnetic field makes an electric field, a changing electric field makes a magnetic field and that this pumping cycle produces an electromagnetic wave…

J. Robert Oppenheimer (1904–1967)

physicist in The Flying Trapeze, Oxford University Press, 1964

ANSWER IS 8*10-6T

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Answer 2

The peak value of magnetic field will be (3)

8 × 10⁻⁸m/s.

Given:

Electric field $=24N/C$

To find:

The peak value of magnetic field.

Solution:

• The Electromagnetic wave is of combination of electric and magnetic field both of which propagates with the speed of light in vacuum $c=3$ × $10^{8}m/s$.
• The electric field and the magnetic fields propagates in a plane perpendicular to each other and also perpendicular to the direction of propagation of the wave.  
• The derived relation between electric field $(E)$ , magnetic field $(B)$ and the speed of light in vacuum $(c)$ is

                                           $c=\frac{E}{B}$

Now, according to the question, substituting the known values in the relation, we get

$c=\frac{E}{B}$

$3$ × $10^{8}$ $=\frac{24}{B}$

$B=\frac{8}{10^{8} }$

$B=8$ × $10^{-8}T$

Final answer:

Hence, the peak value of magnetic field at the point will be (3) 8 × 10⁻⁸m/s.

Although your question is incomplete, you might be referring to the question below.

Electromagnetic wave is propagating in vacuum, at a place magnitude of peak value of electric field is 24 N/C. The peak value of magnetic field at this place is

1. 8 × 10⁴ T
2. 8 × 10⁻⁶ T
3. 8 × 10⁻⁸ T
4. 8 × 10⁻¹⁰ T