Question

Electron configuration of an atom is 2, 8, 7 to which of the following elements would it bechemically similar? [ ]
a) nitrogen(Z=7)
b) fluorine(Z=9)
c) phosphorous(Z=15)
d) argon(Z=18)

Answer 1

Dear Student,

◆ Answer -

(b) Fluorine (Z=9)

● Explanation -

Given that electronic configuration of the unknown atom is 2, 8, 7.

Electronic configuration of Fluorine will be 2, 7.

As no of electrons in last orbit of unknown atom are same as that for fluorine, they will be chemically similar.

Thanks dear. Hope this helps you..

Answer 2

Answer:

correct answer is b) flourine [z=9]

Explanation:

Electronic  configuration of an atom is 2, 8, 7

Chlorine is the element

1s² 2s² 2p⁶ 3s² 3p⁵

valence electron are 7

Period is 3

Group is 17

it belongs to Halogens family .

So element having similar properties to this element[chlorine ] is Fluorine